Question 5 of 5
If specific resistance of a potentiometer wire is [latex]10^{-7},\Omega m[/latex], current flowing through it is 0.1 A and cross-sectional area of wire is [latex]10^{-6},m^2[/latex], then potential gradient will be,
💡 Explanation
Potential gradient [latex]K = \dfrac{I\rho}{A} = \dfrac{(0.1)(10^{-7})}{10^{-6}} = \dfrac{10^{-8}}{10^{-6}} = 10^{-2},V/m[/latex].